Python3嵌套if语句

可能有一种情况,当你想检查另一个条件中的另一个条件解析为 true。 在这种情况下,你可以使用嵌套 if 结构。
在嵌套 if 结构,一个 if...elif...else 的构造里面可以有另一个 if...elif...else 结构。

语法:

嵌套的语法:if...elif...else 的结构可能是:
if expression1:
   statement(s)
   if expression2:
      statement(s)
   elif expression3:
      statement(s)
   else
      statement(s)
elif expression4:
   statement(s)
else:
   statement(s)

示例:

# !/usr/bin/python3
num=int(input("enter number"))
if num%2==0:
    if num%3==0:
        print ("Divisible by 3 and 2")
    else:
        print ("divisible by 2 not divisible by 3")
else:
    if num%3==0:
        print ("divisible by 3 not divisible by 2")
    else:
        print  ("not Divisible by 2 not divisible by 3")

当执行上面的代码,它产生以下结果:
enter number8
divisible by 2 not divisible by 3

enter number15
divisible by 3 not divisible by 2

enter number12
Divisible by 3 and 2

enter number5
not Divisible by 2 not divisible by 3


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